I am very good in world history math and Earth Science By photosynthesis and respiration. 1. The plants utilise carbon dioxide during the photosynthesis. The carbon dioxide is reduced to glucose and oxygen is released by the photolysis of water as by product
2. All organisms including plants utilise oxygen during the process of respiration for the oxidation of glucose and carbondioxide is released. 3
By these processes plants maitain the balance L=1.01m Parameters L = ? g = 10ms^ 2 pi = 22 7 T = 2sec From S.H.M T = 2pisqrt L g Making L the subject of formula T = 2pisqrt L g Divide both sides by color I am very good in world history math and Earth Science By photosynthesis and respiration. 1
The plants utilise carbon dioxide during the photosynthesis. The carbon dioxide is reduced to glucose and oxygen is released by the photolysis of water as by product. 2
All organisms including plants utilise oxygen during the process of respiration for the oxidation of glucose and carbondioxide is released. 3
By these processes plants maitain the balance L=1.01m Parameters L = ? g = 10ms^ 2 pi = 22 7 T = 2sec From S.H.M T = 2pisqrt L g Making L the subject of formula T = 2pisqrt L g Divide both sides by color.
2. All organisms including plants utilise oxygen during the process of respiration for the oxidation of glucose and carbondioxide is released. 3
By these processes plants maitain the balance L=1.01m Parameters L = ? g = 10ms^ 2 pi = 22 7 T = 2sec From S.H.M T = 2pisqrt L g Making L the subject of formula T = 2pisqrt L g Divide both sides by color I am very good in world history math and Earth Science By photosynthesis and respiration. 1
The plants utilise carbon dioxide during the photosynthesis. The carbon dioxide is reduced to glucose and oxygen is released by the photolysis of water as by product. 2
All organisms including plants utilise oxygen during the process of respiration for the oxidation of glucose and carbondioxide is released. 3
By these processes plants maitain the balance L=1.01m Parameters L = ? g = 10ms^ 2 pi = 22 7 T = 2sec From S.H.M T = 2pisqrt L g Making L the subject of formula T = 2pisqrt L g Divide both sides by color.